3.
Hubungan
antara sudut lancip dan komplemennya
latex sin\alpha =\frac{a}{c}=cos(90^\circ -\alpha )
latex cos\alpha =\frac{b}{c}=sin(90^\circ -\alpha )
latex tan\alpha =\frac{a}{b}=cot(90^\circ -\alpha )
latex cot\alpha =\frac{b}{a}=tan(90^\circ -\alpha )
latex sec\alpha =\frac{c}{b}=csc(90^\circ -\alpha )
latex csc\alpha =\frac{c}{a}=sec(90^\circ -\alpha )
Contoh Soal
1.
Diketahui latex tan(\alpha +x)=cot(\alpha -x).
Tentukan sudut latex \alpha .
Jawaban:
latex \begin{array}{rcl}tan(\alpha +x)&=&cot(\alpha -x)\\tan(\alpha +x)&=&tan\Big(90^\circ -(\alpha -x)\Big)\\\alpha +x&=&90^\circ -(\alpha -x)\\2\alpha &=&90^\circ \\\alpha &=&45^\circ \end{array}
2. Untuk sudut
lancip latex x diketahui latex tan\ x adalah dua kali kosinus komplemennya.
Carilah nilai latex x.
Jawaban:
latex \begin{array}{rcl} tanx&=&2\ cos(90^\circ -x)\\tanx&=&2\ sinx\\\frac{sinx}{cosx}&=&2\ sinx\\sinx &=&2\ sinx\ cosx\\2\ sinx\ cosx-sinx&=&0\\sinx(2cosx-1)&=&0\\sinx=0&atau&2cosx-1=0\\x=0^\circ &atau&x=60^\circ \end{array}
3. Buktikan latex \frac{2tan\varphi }{1+tan^2\varphi }=2\ sin\varphi \ sin(90^\circ -\varphi ).
. Jawaban:
latex \begin{array}{rcl} \frac{2\ tan\varphi }{1+tan^2\varphi }&=&\frac{2\ tan\varphi }{sec^2\varphi }\\\\&=&2\ \frac{sin\varphi }{cos\varphi }\ cos^2\varphi \\\\&=&2\ sin\varphi \ cos\varphi \\\\&=&2\ sin\varphi \ sin(90^\circ -\varphi )\end{array}
Terbukti
Adjie Gumarang Pujakelana, 2013
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